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September 2, 2014

September 2, 2014

Posted by **sonia** on Wednesday, November 21, 2012 at 10:21pm.

- calculus -
**Steve**, Thursday, November 22, 2012 at 7:57pmdraw a diagram. If the foot of the ladder is x feet from the fence, and the ladder reaches y feet up the wall, then we have

x/5 = (x+3)/y

y = 5 + 15/x

if the length of the ladder is z,

z^2 = (x+3)^2 + y^2

= (x+3)^2 + (5 + 15/x)^2

z = √((x+3)^2 + (5 + 15/x)^2)

dz/dx = (x+3)(x^3-75) / <a bunch of nonzero junk>

so, dz/dx=0 at x = -3 or ∛75

z^2 = (3+∛75)^2 + (5+15/∛75)^2

z = 11.19 feet

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