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April 19, 2015

Homework Help: chemistry

Posted by allyx3 on Wednesday, November 21, 2012 at 8:11pm.

calculate Cu2+ in a 0.15M CuSO2 (aq) solution that is also 6.5M in free NH3.

Cu^2+(aq)+ 4NH3(aq)<=> [Cu(NH3)4]^2+ kf=1.1*10^13

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