Posted by Rebekah on Wednesday, November 21, 2012 at 6:32am.
recall that
log_a(n) = log_b(n)/log_a(b)
log_a(n) = 1/log_n(a)
1.
log_3(8) * log_8(9)
= 1/log_8(3) * log_8(9)
= log_3(9)
= 2
2.
recall that
e^ln(n) = n, so
e^ln(2^9) = 2^9 = 512
3.
.5 = 1/2, so
ln .5 = ln(2^-1) = -ln(2) = -a
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