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precalculus

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e^3x-7 x e^-2x =4e

First step I get e^1x-7 =4e
For the example in my book, the next step they divided by e. But I have no idea how to do this, or what involves?

  • precalculus -

    You have to apply the indices rule: a^m /a^n= a^(m-n)
    so e^(x-7)/e^1= e^(x-8). We then get: e^(x-8)=4 Use ln: x-8= ln4 so x=8+ln4
    OK?

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