x= 3^log_3_^8 ? The log being in the exponent is throwing me off.
precalculus - Kay, Wednesday, November 21, 2012 at 4:51am
I don't get the question-what are the dashes for?
precalculus - marcus, Wednesday, November 21, 2012 at 6:27am
No reason, basically the equation is supposed to read 3^log base 3^8?
precalculus - Steve, Wednesday, November 21, 2012 at 10:38am
recall the definition of logarithm:
b^log_b(n) = n
3^log_3(8) = 8
log_3(8) is the exponent of 3 which produces 8
log_10(100) = 2 because 10^2 = 100