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August 1, 2014

August 1, 2014

Posted by **marcus** on Wednesday, November 21, 2012 at 2:59am.

- precalculus -
**Kay**, Wednesday, November 21, 2012 at 4:51amI don't get the question-what are the dashes for?

- precalculus -
**marcus**, Wednesday, November 21, 2012 at 6:27amNo reason, basically the equation is supposed to read 3^log base 3^8?

- precalculus -
**Steve**, Wednesday, November 21, 2012 at 10:38amrecall the definition of logarithm:

b^log_b(n) = n

3^log_3(8) = 8

log_3(8) is the exponent of 3 which produces 8

log_10(100) = 2 because 10^2 = 100

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