x= 3^log_3_^8 ? The log being in the exponent is throwing me off.
I don't get the question-what are the dashes for?
No reason, basically the equation is supposed to read 3^log base 3^8?
recall the definition of logarithm:
b^log_b(n) = n
3^log_3(8) = 8
log_3(8) is the exponent of 3 which produces 8
log_10(100) = 2 because 10^2 = 100
The expression x = 3^log_3(8) involves logarithms and exponentiation. To understand and evaluate this expression, we need to break it down step by step.
1. Start by analyzing the logarithm inside the exponent: log_3(8). This logarithm represents the power or exponent to which the base (3) must be raised to obtain the argument (8). In other words, log_3(8) = x means 3^x = 8.
2. Solve the equation 3^x = 8 to find the value of x. Since 3 is the base and 8 is the result of the exponentiation, we can rewrite the equation as 3^x = 3^2. Since the bases are equal, we can equate the exponents and obtain x = 2.
Therefore, x = 3^log_3(8) simplifies to x = 3^2, which means x equals 9.