Posted by **diego sanchez** on Wednesday, November 21, 2012 at 12:37am.

find all the values of X between 0 and 2π such that cos(3x-π/2) = -√3/2

- math -
**drwls**, Wednesday, November 21, 2012 at 1:01am
cos(3x- ƒÎ/2) = sin(3x)

(Check your trig identities)

3x = sin^-1(-ã3/2)

= 4 pi/3, 5 pi/3, 10 pi/3, 11 pi/3 etc

x = 4 pi/9 etc

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