posted by Tara on .
testing bronsted lowry reaction predictions...... im super stuck can someone help me steo by step how to figure this out assuming i use the 5 step process?
write a balanced chemical equation for ch3coona and hcl reaction
position of equilibrium.
I know that ch3coo is a SB
and Hcl is a SA
so reactants are favored and shown as <50% but i cant fiigure out how to write the equation.
Have you been told that ch3coona isn't anything in chemistry. You need to find the caps key for CO, Co and co mean something different just as m and M aren't the same.
I don't have your table of acidic/base values but you do this. You will need to fill in the numbers and decide where th equilibrium is.
CH3COONa ==> CH3COO^- + Na^+
CH3COO^- is a strong base. Na^+ is a spectator ion. CH3COO^- accepts a proton to form CH3COOH.
HCl ==> H3O^+ + Cl^-
H3O^+ is a strong acid. Cl^- is a spectator ion. H3O^+ donates a proton.
CH3COO^- + H3O^+ ==> CH3COOH
This reaction is far to the right.
no i have to teach myself and that's why i was so confused i knew CH3COO would gain a proton but i didn't realize that hcl changed to HCl ==> H3O^+ + Cl^- so it makes a little more sense.I do wanna make sure i understand and i have troubles breaking down the entities. i may ask for more help but only to make sure i am on the right track.
Thank you sooooooo much for helping though
I suppose to make it complete the HCl reacts with H2O as follows:
HCl + H2O ==> H3O^+ + Cl^-
You're quite welcome and come back anytime you have a question. It helps us help you if you explain in detail what you don't understand.