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December 20, 2014

December 20, 2014

Posted by **Zalak** on Tuesday, November 20, 2012 at 10:42pm.

a.What is the height of the cliff in meters?

b.If in part (a) you get two solutions of a quadratic equation and you use one for your answer, what does the other represent?

- Physics -
**drwls**, Wednesday, November 21, 2012 at 12:16amLet H be the height of the cliff. The the time required to fall a distance d is

t = sqrt(2d/g)

From the information given you can write:

sqrt(2H/g) - sqrt[(2/3)*2H/g] = 1.3

sqrt(2H/g)*[1 - sqrt(2/3)] = 1.3

0.1835*sqrt(2H/g)= 1.3

sqrt(2H/g) = 7.08

H = 246 m

Check: 2/3 of the way down is 164 m

Time to fall 164 m = 5.785 s

Time to fall 246 m = 7.085 s

Difference = 1.30 s

I did not have to solve a quadratic equation.

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