Posted by patel on .
Two constant forces act on an object of mass m = 4.50 kg object moving in the xy plane as shown in the figure below. Force 1 is 21.0 N at 35.0°, and force 2 is 47.0 N at 150°. At time t = 0, the object is at the origin and has velocity (3.70 + 2.25) m/s.
(a) Express the two forces in unit-vector notation.
1 = N
2 = N
(b) Find the total force exerted on the object.
(c) Find the object's acceleration.
Now, consider the instant t = 3.00 s.
(d) Find the object's velocity.
(e) Find its position.
(f) Find its kinetic energy from ½mvf2.
(g) Find its kinetic energy from ½mvi2 + Σ · Δ.
(h) What conclusion can you draw by comparing the answers to parts (f) and (g)?