The density of ice is 0.9168 g/cm3.

The density of water is 0.9998 g/cm3.
Calculate the difference between ΔU (internal energy) and ΔH (enthalpy) during the fusion of 2.5 moles of ice at atmospheric pressure.

change in enthalpy= 6.3

To calculate the difference between ΔU (internal energy) and ΔH (enthalpy) during the fusion of 2.5 moles of ice at atmospheric pressure, we need to use the equation:

ΔH = ΔU + PΔV

Where:
ΔH = Enthalpy change
ΔU = Internal energy change
P = Pressure
ΔV = Volume change

In this case, ice is undergoing fusion (melting) at atmospheric pressure. During the fusion process, the volume remains constant as long as the pressure is constant.

Therefore, ΔV is zero, and the equation simplifies to:

ΔH = ΔU

So, the difference between ΔU and ΔH during the fusion of 2.5 moles of ice at atmospheric pressure is zero.