precalc help !!!!!!!
posted by Haley on .
cos^2xsin^2 x+1=cos x

sin^2 x = 1  cos^2 x
so we have
cos^2 x  1 + cos^2 x + 1
or
2 cos^2 x
on the left
so
2 cos^2 x = cos x
cos x = 1/2
x = 60 degrees or pi/3 radians
or
300 degrees or 5 pi/3 radians 
from Damon's middle section:
2cos^2 x  cosx = 0
cosx(2cosx  1) = 0
cosx = 0 or cosx = 1/2
so from cosx=1/2 we have the 2 answers that Damon gave
from cosx = 0 , we also have
x = 90° or x = 270°
x = π/2 or x = 3π/2