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November 24, 2014

November 24, 2014

Posted by **bülent** on Tuesday, November 20, 2012 at 2:09pm.

the figure is

htt p://s2.dosya.tc/server22/DIDqtx/P043figure.png. html

a) What is the maximum compression of the spring?

(in m) 2.731 m

b) How long will it take after the collision to reach this maximum compression?

(in s) 0.6857 s

i tried everything ,just found out the second one but still have a problem about the first one.

- university physics -
**Damon**, Tuesday, November 20, 2012 at 2:34pmFirst find the speed after collision from conservation of momentum

initial momentum:

m v = 5.29 * 15.3 = 80.9 which will be momentum after crash

after crash

m = 5.29+7.65 = 12.94 kg

so for v after crash:

12.94 v = 80.9

v = 6.25 m/s after crash

v at end is zero and energy after crash is conserved so

(1/2)(12.94)(6.25)^2 = (1/2) (67.9) x^2

x^2 = 7.45

and

x = 2.73 meters I agree

time = 1/4 of period T

T = 2 pi sqrt(m/k)

= 2 pi sqrt (12.94/67.9)

= 2.74 seconds

1/4 T = .6857 seconds sure enough

- university physics -
**bülent**, Thursday, November 22, 2012 at 11:09amthank you!

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