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October 25, 2014

October 25, 2014

Posted by **Ella** on Tuesday, November 20, 2012 at 1:06pm.

in a 0 degrees Celsius ice bath and 253.8 ohms when immersed in a crucible contacting melting potassium. What is the

melting point of potassium? Hint: First determine the resistance of the platinum resistance

thermometer at room temperature, 20 degrees Celsius.

- university physics -
**Elena**, Tuesday, November 20, 2012 at 3:39pmfor Pt α =0.00392 (1/℃).

R₁=R₀[1+α(T₁-T₀)]

R₂= R₀[1+α(T₂-T₀)]

R₁/R₂=[1+α(T₁-T₀)]/[1+α(T₂-T₀)]

200/253.8=(1- 0.00392 •20)/[1+ 0.00392• (T₂-20)]

Solving for T₂ gives

T₂=63.2℃

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