Posted by Ella on Tuesday, November 20, 2012 at 1:06pm.
for Pt α =0.00392 (1/℃).
R₁=R₀[1+α(T₁-T₀)]
R₂= R₀[1+α(T₂-T₀)]
R₁/R₂=[1+α(T₁-T₀)]/[1+α(T₂-T₀)]
200/253.8=(1- 0.00392 •20)/[1+ 0.00392• (T₂-20)]
Solving for T₂ gives
T₂=63.2℃
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