Posted by **JOAN** on Tuesday, November 20, 2012 at 7:22am.

while exploring a cave, a spelunker starts at the entrance and moves the following distances in a horizontal plane. she goes 75.0 m north, 250 m east, 125 m at an angle theta equal to 30.0 north of east, and 150 m south. find her resultant displacement from the cave entrance.

- PHYSICS -
**Steve**, Tuesday, November 20, 2012 at 10:24am
the displacement for each leg of the journey is

(0,75)

(250,0)

(108.25,62.5) since x=125cos30°, y=125sin30°

(0,-150)

add 'em up to get

(358.25,-12.5)

358.5m final displacement.

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