Post a New Question


posted by .

Use the tangent line approximation to approximate the value of ln(1008)

  • calculus -

    assuming you want to use an "easily" calculatable value, let's approximate assuming we know the value of ln(1000).

    the slope of the tangent at any point (x,y) on the curve is

    m = 1/x

    so, at x=1000, the slope is 1/1000.

    Thus, we are using the line through (1000,ln1000) with slope 1/1000:

    y = 1/1000 (x-1000) + ln1000
    at x=1008,
    y = 8/1000 + ln1000 = 6.915755

    real value: 6.915723

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question