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October 30, 2014

October 30, 2014

Posted by **paul** on Monday, November 19, 2012 at 10:25pm.

- calculus -
**Steve**, Tuesday, November 20, 2012 at 12:08amassuming you want to use an "easily" calculatable value, let's approximate assuming we know the value of ln(1000).

the slope of the tangent at any point (x,y) on the curve is

m = 1/x

so, at x=1000, the slope is 1/1000.

Thus, we are using the line through (1000,ln1000) with slope 1/1000:

y = 1/1000 (x-1000) + ln1000

at x=1008,

y = 8/1000 + ln1000 = 6.915755

real value: 6.915723

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