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Posted by **paul** on Monday, November 19, 2012 at 10:16pm.

- calculus -
**MathematicsPro**, Monday, November 19, 2012 at 10:17pmvbr{lr<5vvx><f(nn)/.bbn>

vbr<lr><5.12>(9.8)^3

.bbn=%ff

%ff=F(9x)

.bbn=%ff9x

.bbn=.133%tri

.bbn=.tri

t.ri=vbr

v=161.2

b=39.1

r=12.7

Sub in the inverse values of vbr - calculus -
**Reiny**, Monday, November 19, 2012 at 11:04pmg ' (x) = -107 sin(107x)