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Posted by on Monday, November 19, 2012 at 10:16pm.

Find the derivative of g(x)=cos(107x)

  • calculus - , Monday, November 19, 2012 at 10:17pm

    vbr{lr<5vvx><f(nn)/.bbn>
    vbr<lr><5.12>(9.8)^3
    .bbn=%ff
    %ff=F(9x)
    .bbn=%ff9x
    .bbn=.133%tri
    .bbn=.tri
    t.ri=vbr
    v=161.2
    b=39.1
    r=12.7

    Sub in the inverse values of vbr

  • calculus - , Monday, November 19, 2012 at 11:04pm

    g ' (x) = -107 sin(107x)

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