calculus
posted by paul on .
Find the derivative of g(x)=cos(107x)

vbr{lr<5vvx><f(nn)/.bbn>
vbr<lr><5.12>(9.8)^3
.bbn=%ff
%ff=F(9x)
.bbn=%ff9x
.bbn=.133%tri
.bbn=.tri
t.ri=vbr
v=161.2
b=39.1
r=12.7
Sub in the inverse values of vbr 
g ' (x) = 107 sin(107x)