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September 1, 2014

September 1, 2014

Posted by **Amina** on Monday, November 19, 2012 at 9:56pm.

- math -
**Reiny**, Monday, November 19, 2012 at 11:02pmr^2 = (-3/5)^2 + 2^2 = 109/25

r = √109/5

since (3/5,2) is in quadrant II

sinØ = 2/(√109/5) = 10/√109

cscØ = √109/10

cosØ = (-3/5) /(√109/5) = -3/√109

secØ = -√109/3

tanØ = 2/(-3/5) = -10/3

cotØ = -3/10

btw Ø = appr 106.7°

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