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September 24, 2014

September 24, 2014

Posted by **amy** on Monday, November 19, 2012 at 4:50pm.

- calculus -
**Reiny**, Monday, November 19, 2012 at 5:13pmMake a diagram showing the height h, the horizontal distance 500 m and the the angle Ø.

tanØ = h/500

h = 500 tanØ

dh/dt = 500 sec^2 Ø dØ/dt

when h = 800

the hypotenuse = 100√89

and sec^2 Ø = 89/25

100 = 500(89/25) dØ/dt

dØ/dt = 25(100)/(500(89)) = 5/89 or appr .0562 radians/sec

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