Posted by amy on Monday, November 19, 2012 at 4:50pm.
Make a diagram showing the height h, the horizontal distance 500 m and the the angle Ø.
tanØ = h/500
h = 500 tanØ
dh/dt = 500 sec^2 Ø dØ/dt
when h = 800
the hypotenuse = 100√89
and sec^2 Ø = 89/25
100 = 500(89/25) dØ/dt
dØ/dt = 25(100)/(500(89)) = 5/89 or appr .0562 radians/sec
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