Posted by **nicole** on Monday, November 19, 2012 at 3:33pm.

your house sits on a rectangular lot that has a perimeter of 320 feet. you want to fence the two sides and the back of your lot. your neighbor on the back end wants to have a concrete frence that costs $16 per foot. your side neighbors do not want such an expensive fence and will settle for a fence that is $15 per foot. you received a bid from a local fence company for a total cost of $3134. how much will be your share of the cost assuming your two side neighbors will go in 1/2 (your back neighbor will not help you pay for the fence.)

- Intermediate Algebra -
**Steve**, Monday, November 19, 2012 at 3:42pm
You don't specify the dimensions of the lot, but we do know that

2(width+length) = 320

length = 160-width

fence costs 2(15w)+16(160-w) = 3134

w = 41

so, the lot is 41x119

119*16 = 1904 for the back fence

82*15 = 1230 for the two side fences

your share 1904 + 1/2 (1230) = 2519

## Answer this Question

## Related Questions

- Calculus - a college is planning to construct a new parking lot. the parking lot...
- Calculus - a college is planning to construct a new parking lot. the parking lot...
- math - A triangular lot sits at the corner of two streets that intersect at an ...
- Algebra - a rectangular lot whose perimeter is 1600 feet is fenced on three ...
- college algebra - a rectangular lot whose perimeter is 440 feet is fenced along ...
- Algebra - You plan to put a fence around a rectangular lot. The length of the ...
- Algebra - The length of a rectangular parking lot is 4 times its width w. The ...
- diff calculus - 1.) triangular corner lot has perpendicular sides of lengths 120...
- Algebra - The perimeter of a rectangular lot is 190 ft. The width of the lot is ...
- Intermediate algebra, concepts and graphs - A garden is in the shape of a square...