Posted by **Stacey** on Monday, November 19, 2012 at 2:31pm.

A length of wire has a radius of 3.00 x 10-3 m and a resistance of 0.200 ohms. When the potential

difference across the wire is 10.0 volts, the electron drift speed is found to be 2.98 x10-4 m/s. On the

basis of these data, calculate the density of free electrons in the wire.

- physics, university -
**Elena**, Monday, November 19, 2012 at 3:12pm
J=nev,

where

J is the current density,

n is free electron density,

e=1.6•10⁻¹⁹C ,

drift velocity v= 2.98•10⁻⁴ m/s

J=U/RA,

where

U=10 V,

R=0.2 Ω,

A= πr²

n•e•v= U/R•π•r²

n= U/R•π•r²• e•v=...

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