Post a New Question

physics, university

posted by on .

A length of wire has a radius of 3.00 x 10-3 m and a resistance of 0.200 ohms. When the potential
difference across the wire is 10.0 volts, the electron drift speed is found to be 2.98 x10-4 m/s. On the
basis of these data, calculate the density of free electrons in the wire.

  • physics, university - ,

    J=nev,
    where
    J is the current density,
    n is free electron density,
    e=1.6•10⁻¹⁹C ,
    drift velocity v= 2.98•10⁻⁴ m/s
    J=U/RA,
    where
    U=10 V,
    R=0.2 Ω,
    A= πr²
    n•e•v= U/R•π•r²
    n= U/R•π•r²• e•v=...

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question