Posted by Anonymous on .
A daredevil decides to jump a canyon of width
8.4 m. To do so, he drives a motorcycle up an
incline sloped at an angle of 12.6
The acceleration of gravity is 9.8 m/s
What minimum speed must he have in order to clear the canyon?
Answer in units of m/s
for a projectile fired with velocity v at angle θ, the range is
r = (v^2 sin2θ)/g
8.4 <= v^2/9.8 sin12.6°
v^2 >= 8.4*9.8/.218
v^2 >= 377.61
v >= 19.4 m/s