Posted by Tracy on Monday, November 19, 2012 at 12:26pm.
I need to know exactly what your problem is in working this.
Part a is just a matter of plugging into the Kc expression and solve for Kc.
Part b appears to me nothing more than adding 1.5 to the I2 equilibrium amount and recalculating Kc (which would now be called Q).
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