A refrigerator has a coefficient of performance of 4.0. When removing 2.4x10^4 J from inside the refrigerator, how much energy is sent into the environment?

Coefficient of performance = energy removed from fridge / ( total energy expelled – energy removed from fridge )

k=Q1/(Q-Q1)
Q=Q1(k+1)/k=2.4•10⁴•5/4=3•10⁴ J

Why did the refrigerator start a stand-up comedy routine?

Because it wanted to blow off some "cool" jokes!

Now, let's calculate the energy sent into the environment. The coefficient of performance (COP) of a refrigerator is defined as the ratio of the heat removed from inside the refrigerator (Qin) to the work done on the refrigerator (W). It can be given by COP = Qin / W.

In this case, the COP is 4.0, which means that for every 1 unit of work done, 4 units of heat are removed.

We know that the refrigerator removes 2.4x10^4 J from inside, so we can set up the equation:

4 = 2.4x10^4 J / W

Cross-multiplying and solving for W, we get:

W = 2.4x10^4 J / 4
W = 6x10^3 J

Therefore, the refrigerator sends 6x10^3 J of energy into the environment to remove 2.4x10^4 J from inside. But hey, don't worry, it's just giving back a little heat to keep things cool!

To find the amount of energy sent into the environment, we need to use the equation:

Energy sent into environment = Energy removed from inside the refrigerator / Coefficient of Performance

Let's substitute the given values into the equation:

Energy removed from inside the refrigerator = 2.4x10^4 J
Coefficient of Performance = 4.0

Now, we can calculate the energy sent into the environment:

Energy sent into environment = (2.4x10^4 J) / (4.0)
Energy sent into environment = 6.0x10^3 J

Therefore, the amount of energy sent into the environment is 6.0x10^3 J.

To calculate the amount of energy sent into the environment, we need to use the equation:

Energy input = Energy output / Coefficient of Performance (COP)

In this case, the energy output is the amount of energy being removed from inside the refrigerator, which is given as 2.4x10^4 J. The coefficient of performance (COP) is given as 4.0.

Substituting these values into the equation, we get:

Energy input = 2.4x10^4 J / 4.0

Calculating this expression, we get:

Energy input = 6.0x10^3 J

Therefore, when removing 2.4x10^4 J from inside the refrigerator, 6.0x10^3 J of energy is sent into the environment.