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October 21, 2014

October 21, 2014

Posted by **Eric** on Monday, November 19, 2012 at 11:26am.

- Math -
**Ms. Sue**, Monday, November 19, 2012 at 11:32am - Math -
**mathtaculator**, Monday, November 19, 2012 at 11:41amsorry i dont see a picture. But, I'll explain what should be seen. Make a right triangle. From the angle <B, where B is 90 degrees, draw an altitude down to CA. Call that point D. We see that ABC and BCD are similar triangles. BC/CD=AC/BC, so BC^2=AC*CD. Likewise, ADB is similar to ABC, so we get AB/AD=AC/AB, so AB^2=AD*AC.So we add these equations together for BC^2 and AB^2, to get AC*CD + AD*AC = AC(CD+AD) = AC^2 Thus, a^2 + b^2 = c^2 in a right triangle.

- Math -
**mathtaculator**, Monday, November 19, 2012 at 11:46amBTW, A would be at the top if the right triangle were standing on its shorter base. C would be on the other side on the bottom right. B would be on the right angle

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