Posted by JOAN on Monday, November 19, 2012 at 11:10am.
while exploring a cave, a spelunker starts at the entrance and moves the following distances in a horizontal plane. she goes 75.o m north, 250 m east, 125 m at angle theta =30.0 north of east, and 150 m south. find her resultant displacement from the cave entrance.

PHYSICS  Steve, Monday, November 19, 2012 at 11:27am
the displacement for each leg of the journey is
(0,75)
(250,0)
(108.25,62.5)
(0,150)
add 'em up to get
(358.25,12.5)
358.5m final displacement.

PHYSICS  JOAN, Tuesday, November 20, 2012 at 7:51am
how did you get (108.25,62.5) and (0,150)
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