Posted by **JOAN** on Monday, November 19, 2012 at 11:10am.

while exploring a cave, a spelunker starts at the entrance and moves the following distances in a horizontal plane. she goes 75.o m north, 250 m east, 125 m at angle theta =30.0 north of east, and 150 m south. find her resultant displacement from the cave entrance.

- PHYSICS -
**Steve**, Monday, November 19, 2012 at 11:27am
the displacement for each leg of the journey is

(0,75)

(250,0)

(108.25,62.5)

(0,-150)

add 'em up to get

(358.25,-12.5)

358.5m final displacement.

- PHYSICS -
**JOAN**, Tuesday, November 20, 2012 at 7:51am
how did you get (108.25,62.5) and (0,-150)

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