Posted by selly on Monday, November 19, 2012 at 6:35am.
Answer : 2.4227*10^-3
i.e. 0.002423
thanks
Information
density Si=2.33 g/cc
Mw(P)=10.81 g/mole
NA=6.022*10^23 at/mole
V (Si)=1 Kg *1000 g/Kg /(2.33 g/cc = 4.29*10^2 cc
moles B/cc = 3.091*10^17 carriers/cc /6.022*10^23 =5.133*10^-7 moles B/cc
moles B= 5.133*10^-7 moles/cc *4.29*10^2 cc= 2.203*10^-4 moles B
g B= 2.203*10^-4 moles * 10.81 g/mole = 2.4227*10^-3 g
Related Questions
Basic Engineering2. Materials Science - Boron is used to dope 1 kg of germanium...
chemistry - Boron, germanium, aluminum, silicon and antimony are all semimetals ...
chemistry - Use demensional analysis to convert 4.68 grams of boron to cubic ...
Chemistry - A p-n junction is to be created by diffusing boron (B) into an n-...
Chemistry - In the manufacturing of computer chips, cylinders of silicon are cut...
chemistry - What is the maximum amount of ethanol (in grams) that can be ...
Chemistry - Boron has only two naturally occurring isotopes. The mass of boron-...
CHEM - Silicon carbide, commonly known as carborundum, is a very hard and ...
chemistry - When 50 g of silicon dioxide is heated with an excess of carbon, 32....
Chemistry - Which of the following surfaces does a true monolayer always form ...
For Further Reading