Posted by Anonymous on Monday, November 19, 2012 at 3:29am.
You can try a proportional one-sample z-test for this one since this problem is using proportions.
Using a formula for a proportional one-sample z-test with your data included, we have:
z = .225 - .30 -->test value (45/200) is .225) minus population value (.30) divided by
√[(.30)(.70)/200] --> .70 represents 1-.30 and 200 is sample size.
Finish the calculation. I'll let you take it from here.
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