Posted by Kevin pls it's due at midnight :( on Sunday, November 18, 2012 at 9:10pm.
........Ca(OH)2 ==> Ca^2+ + 2OH^-
I.......solid........0.......0
C.......solid........x.......2x
E.......solid........x.......2x
Ksp = 6.5E-6 = (Ca^2+)(OH^-)^2
6.5E-6 = (x)(2x)^2 = 4x^3
Solve for x = [Ca(OH)2] in mols/L
Convert that to grams/500 mL.
g = mols x molar mass and that divided by 2 = g/500. Compare with the 0.37 g in the problem. If 0.37 g is larger than x the soln is not saturated. If 0.37 g is smaller it is saturated.
Thank you so much!
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