Chemistry
posted by Michelle on .
What mass of Uranium (in mg) is contained in 1ml of 4.55M (UO2)3(PO4)3 solution?
How do I solve this?
*all numbers are subscripts

How many mols do you have? That's M x L = mols.
There are 3 atoms U in 1 molecule of (UO2)3(PO4)3; therefore mols (UO2)3(PO4)3 x 3 = mols U
g U = mols U x atomic mass U.
Convert g to mg.