Calculus [finding slope of tangent line]
posted by Ali .
Find the slope of the tangent line to the curve 0x^2−2xy+2y^3=10 at point (-4,1)
Help please? Thanks in advance
Don't know why you bother with the zero:
(yes, (-4,1) is on that graph.
just use the product rule, remembering that x' = 1:
-2yx' - 2xy' + 6yy' = 0
-2y + (6y-2x)y' = 0
y' = 2y/(6y-2x)
y' = 2(1)/(6(1)-2(-4)) = 2/(6+8) = 1/7