Posted by MATTHEW GOWOK POLIT on .
1. A body of mass 400g dropped from a height of 30m. If after rebounce the ball loses 2/3 of its energy, calculate: <a>.the velocity before bounce, .the height after rebounce, <c>.the velocity after rebounce
a. V^2 = Vo^2 + 2g*d.
V^2 = 0 + 19.6*30 = 588
V = 24.2 m/s.