Friday
April 18, 2014

Homework Help: chemistry... HELP !!!!!!!

Posted by sarah on Sunday, November 18, 2012 at 12:40pm.

The average bond enthalpy for C__H is 413 kJ/mol. In other words, 413 kJ of energy is required to break a mole of CH into atoms:
CH (g) ----> C(g) + H(g) delta H= 413 kJ

Using this information, and enthalpy of C6H6=5535kJ, calculate the enthalpy change of the reaction:
C6H6 (g) --> 6CH (g)

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

chemistry - N2(g) + 3 F2(g) → 2 NF3(g) ΔH = 264 kJ/mol ΔS = ...
help plz - Bond enthalpy is the energy required to break a mole of a certain ...
CHem help pkz - Bond enthalpy is the energy required to break a mole of a ...
CHEMISTRY - Please explain. The average bond enthalpy for the C-H bond is 412 kJ...
Chemistry - Please explain. The average bond enthalpy for the C-H bond is 412 kJ...
chemistry - N2(g) + 3 F2(g) → 2 NF3(g) ΔH = 264 kJ/mol ΔS = ...
Chemistry - i tried to do like dis plz chk is it rite or wrong. [2(4(327) + 495...
Chem - Bond enthalpy is the energy required to break a mole of a certain type of...
chemistry - 2H2 + O2 yield 2H2O to calculate bond enthalpy, we have to take bond...
Chemistry - H(f) Cl= 121.3 kj H(f) C= 716.7 H(f) CCl4= -95.7 calculate the ...

Search
Members