algebra
posted by lee on .
What are the zeros of the function? what are their multiplicities
f(x)=4x^320x^2+24x
numbers 3,2,and 0 are multiplicity of 1
numbers 3,2,and 0 are multiplicity of 1

Common factor of
4 x ^ 3  20 x ^ 2 + 24 x
are 4x
4 x ^ 3  20 x ^ 2 + 24 x / 4
x =
x ^ 2  5 x + 6
OR
4 x ^ 3  20 x ^ 2 + 24 x = 4 x * ( x ^ 2  5 x + 6 )
4 x = 0 when x = 0
Solutions of equation :
x ^ 2  5 x + 6
are
x = 2 and x = 3
Solutions of equation :
4 x ^ 3  20 x ^ 2 + 24 x = 0
are
x = 0
x = 2 and
x = 3 
thank you