Tuesday

October 21, 2014

October 21, 2014

Posted by **Ashwin** on Sunday, November 18, 2012 at 7:08am.

- Math -
**Steve**, Sunday, November 18, 2012 at 3:03pmgotta get creative with this one. Note that

x^4+x^2+16 = x^4-8x^2+16 - 9x^2 = (x^2-4)^2 - (3x)^2

= (x^2-4)^2 [(3x/(x^2-4)^2)^2 + 1]

so, if you let u = 3x/(x^2-4)

du = -3(x^2+4)/(x^2-4)^2 and you have

integral -1/3 du/(1+u^2)

take it from there!

**Answer this Question**

**Related Questions**

Calculus - Evaluate the integral: 16csc(x) dx from pi/2 to pi (and determine if ...

Math - 1) evaluate integral of xe^3x dx 2) evaluate integral form 1 to 0 of 4e^...

Math - 1) evaluate: integral of (3x^2 + 5x - 1 + 3/x) dx x^3/3 + x^2/5 - x Is ...

Math - 1. Evaluate the indefinite integral ([6x^2 + 12x^(3/2) +4x+9]/sqrt x)dx. ...

Math(Please check) - evaluate the integral integral of 3 to 2 x/(x^2-2)^2 dx u=x...

math - evaluate the double integral and reverse order of integration [(first ...

math - Evaluate the following indefinite integral by using the given ...

math - Evaluate the following indefinite integral by using the given ...

Calculus II/III - A. Find the integral of the following function. Integral of (x...

Calculus - integral -oo, oo [(2x)/(x^2+1)^2] dx (a) state why the integral is ...