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September 30, 2014

September 30, 2014

Posted by **Ashwin** on Sunday, November 18, 2012 at 7:08am.

- Math -
**Steve**, Sunday, November 18, 2012 at 3:03pmgotta get creative with this one. Note that

x^4+x^2+16 = x^4-8x^2+16 - 9x^2 = (x^2-4)^2 - (3x)^2

= (x^2-4)^2 [(3x/(x^2-4)^2)^2 + 1]

so, if you let u = 3x/(x^2-4)

du = -3(x^2+4)/(x^2-4)^2 and you have

integral -1/3 du/(1+u^2)

take it from there!

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