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Posted by on Sunday, November 18, 2012 at 6:33am.

Sulfur vapor is analyzed by photoelectron spectroscopy (PES). Measurements determine that photoelectrons associated with the 1st ionization energy of sulfur move with de Broglie wavelength λ=2.091 A˚. What is the maximum wavelength (in meters) of radiation capable of ionizing sulfur and producing this effect?

  • chemistry - , Sunday, November 18, 2012 at 9:46am

    could somebody just post the solution process or post the formula? thanx a lot

  • chemistry - , Sunday, November 18, 2012 at 10:03am

    E=hv
    E=E(A)-B
    lambda=hc/lambda

  • chemistry - , Sunday, November 18, 2012 at 10:08am

    what does E=E(A)-B mean?

  • chemistry - , Sunday, November 18, 2012 at 10:20am

    if i solve it by last equation i get something with 2.xxxxx*10^-7
    could this be the right solution?

  • chemistry - , Sunday, November 18, 2012 at 12:02pm

    helloooo? please somebody answer...
    now i have a bunch of solutions here but i cant figure out the right one and

  • chemistry - , Sunday, November 18, 2012 at 12:28pm

    Which equation using?. help me thanks

  • chemistry - , Sunday, November 18, 2012 at 4:01pm

    Can someone post the right equation please?

  • chemistry - , Sunday, November 18, 2012 at 11:06pm

    p=h/lambda(meters) ,
    E= p^2/2m + 1.659*10^-18,
    LambdaMax=hc/E

  • chemistry - , Sunday, November 18, 2012 at 11:40pm

    Is the answer 116016636.521?

  • chemistry - , Sunday, November 18, 2012 at 11:47pm

    No...is the answer0.116016636521?

  • chemistry - , Sunday, November 18, 2012 at 11:54pm

    is the answer 0.116016636521?

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