Posted by Adam on .
Suppose you would like to cross a 209foot wide river in a boat. Assume that the boat can travel 32 mph relative to the water and that the current is flowing west at the rate of 6 mph. If the bearing chosen is chosen so that the boat will land at a point exactly across from its starting loin, how long will it take for the boat to make the crossing? Give your answer to the nearest second.

Trig 
Steve,
if the boat travels s seconds,
1 km/hr = 1.4667 ft/s
209^2 + (6*1.4667s)^2 = (32*1.4667s)^2
s = 4.5 sec 
Trig 
A. J.,
1 mile/hr=1.46667 ft/sec. The KM here is a typo. The rest o the problem is good and correct. Giving direction on how to draw a diagram to visualize would have been be great.
Thanks and keep up the good work.