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Suppose you would like to cross a 209-foot wide river in a boat. Assume that the boat can travel 32 mph relative to the water and that the current is flowing west at the rate of 6 mph. If the bearing chosen is chosen so that the boat will land at a point exactly across from its starting loin, how long will it take for the boat to make the crossing? Give your answer to the nearest second.

  • Trig - ,

    if the boat travels s seconds,
    1 km/hr = 1.4667 ft/s

    209^2 + (6*1.4667s)^2 = (32*1.4667s)^2
    s = 4.5 sec

  • Trig - ,

    1 mile/hr=1.46667 ft/sec. The KM here is a typo. The rest o the problem is good and correct. Giving direction on how to draw a diagram to visualize would have been be great.

    Thanks and keep up the good work.

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