Posted by Ashley on Saturday, November 17, 2012 at 8:53pm.
How long does it take to fall 17.2 inches.
(I assume you are working with an ancient text that uses feet and inches so in your world g = 32 ft/s^2)
17.2 inches /12 in/ft = 1.43 ft
d = 1.43 = (1/2) g t^2
1.43 = 16 t^2
t = .299 seconds to fall
So horizontal speed u took us 1.61 inches in .299 seconds
1.61/12 = u (.299)
so u = .449 ft/second
Call ball speed s
total x momentum of system before catch = momentum of ball = .43 s
so
.43 s = u(80.43) = .449 (80.43)
so
s = 84 ft/s
How long does it take to fall 17.2 inches.
(I assume you are working with an ancient text that uses feet and inches so in your world g = 32 ft/s^2)
17.2 inches /12 in/ft = 1.43 ft
d = 1.43 = (1/2) g t^2
1.43 = 16 t^2
t = .299 seconds to fall
So horizontal speed u took us 1.61 inches in .299 seconds
1.61/12 = u (.299)
so u = .449 ft/second
Call ball speed s
total x momentum of system before catch = momentum of ball = .43 s
so
.43 s = u(80.43) = .449 (80.43)
so
s = 84 ft/s
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