Posted by Anonymous on Saturday, November 17, 2012 at 7:23pm.
Solve for x.
- Algebra 2.. - Steve, Saturday, November 17, 2012 at 10:22pm
let z = 2^x, and you have
z^4 - 1/z^2 + 2 = 4
(z^6 - 1)/z^2 = 2
don't like that. How about
(z^4 - 1)/(z^3 + 2) = 4
z^4 - 1 = 4z^3 + 8
z^4 - 4z^3 - 9 = 0
still no joy. You sure there's no typo somewhere?
Ah. how about
2^(4x-1) / 2^(3x+2) = 4
since we're dividing, subtract exponents to get
2^(x-3) = 4
now, 4 = 2^2, so we have
2^(x-3) = 2^2
x-3 = 2
x = 5
See how important parentheses can be?
- Algebra 2.. - Anonymous, Saturday, November 17, 2012 at 11:49pm
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