Posted by Anonymous on Saturday, November 17, 2012 at 7:23pm.
Solve for x.
- Algebra 2.. - Steve, Saturday, November 17, 2012 at 10:22pm
let z = 2^x, and you have
z^4 - 1/z^2 + 2 = 4
(z^6 - 1)/z^2 = 2
don't like that. How about
(z^4 - 1)/(z^3 + 2) = 4
z^4 - 1 = 4z^3 + 8
z^4 - 4z^3 - 9 = 0
still no joy. You sure there's no typo somewhere?
Ah. how about
2^(4x-1) / 2^(3x+2) = 4
since we're dividing, subtract exponents to get
2^(x-3) = 4
now, 4 = 2^2, so we have
2^(x-3) = 2^2
x-3 = 2
x = 5
See how important parentheses can be?
- Algebra 2.. - Anonymous, Saturday, November 17, 2012 at 11:49pm
Answer this Question
More Related Questions
- Math - We have an important chemsitry test due and I want to make sure that I do...
- Intermediate Algebra - Combine like terms: -3x^2+2x-4x^2-9+6x-2x^2+8 Solve for x...
- algebra - Solve the indicated variable: 1. Volume of a cone: solve for h: V=Ļir^...
- Algebra - Solve for x: h=(k/4)(x-3L) Solve for B: v-6Bxk=7B Solve for S: z+(1/7)...
- Algebra - Hi, how would I solve these 2 equations using algebra? It states in ...
- Algebra 2 - Solve each system 3x+2y= -2 9x- y= -6 I know how to solve for x but ...
- Algebra 2 - How do I solve these inequalities: e^3x>e^x-1 -6log (subscript of...
- algebra - solve for the indicated variable: a. temperature formula solve for F: ...
- Algebra - FIND THE GCF OF THE PRODUCT (3B+6)(2B-10) SOLVE... X^2=-6X x(x+6)= 0 x...
- algebra - im trying to solve a literal equation, then solve the specific ...