A 1.31-kg block slides across a rough surface such that it slows down with an acceleration of 1.39 m/s2. What is the coefficient of kinetic friction between the block and the surface?
Physics - Brenda, Saturday, November 17, 2012 at 5:57pm
I think you solve it like this...do you have the answer to verify? I am no genius in physics...
Forces in the x direction = friction = mass x acceleration.
friction forces is found by multiplying the coefficient of friction (u) by the normal force.
so. -u x mass x gravity = mass x -acceleration
mass cancels so u = 1.39 / 9.8.
Physics - Damon, Saturday, November 17, 2012 at 6:01pm
atta go Brenda !