Titanium (Ti) can be produced by the reaction of metallic sodium (Na) with titanium tetrachloride vapor (TiCl4). The byproduct of this reaction is sodium chloride (NaCl). Calculate the amount of titanium produced (in kg) when a reactor is charged with 61.0 kg of TiCl4 and 9.0 kg of Na.

did you get an answer?

4.684

(Kg og Na)/ 23*4 =X

X * 47.88 = in g

convert to Kg

10.4

To calculate the amount of titanium (Ti) produced, we need to determine the limiting reactant in the reaction. The limiting reactant is the reactant that is completely consumed and limits the amount of product that can be formed.

First, let's calculate the moles of each reactant using their molar masses:

Molar mass of TiCl4 = 47.87 g/mol (Ti: 47.867 g/mol, Cl: 4 x 35.453 g/mol)
Molar mass of Na = 22.99 g/mol
Molar mass of Ti = 47.867 g/mol

1. Moles of TiCl4 = mass / molar mass = 61.0 kg * 1000 g/kg / 47.87 g/mol = 1274.68 mol
2. Moles of Na = mass / molar mass = 9.0 kg * 1000 g/kg / 22.99 g/mol = 391.04 mol

Next, let's set up the balanced chemical equation for the reaction:

2 Na + TiCl4 -> Ti + 2 NaCl

This equation tells us that 2 moles of Na react with 1 mole of TiCl4 to produce 1 mole of Ti.

To determine the limiting reactant, we need to compare the moles of Na and TiCl4. The reactant that produces fewer moles of product (Ti) is the limiting reactant.

3. Moles of Ti produced (from Na) = 2 * moles of Na = 2 * 391.04 mol = 782.08 mol

Since we have more moles of TiCl4 (1274.68 mol) than Na, Na is the limiting reactant.

Finally, let's calculate the mass of Ti produced:

Moles of Ti produced = 1 mole (from the balanced equation)
Molar mass of Ti = 47.867 g/mol

4. Mass of Ti produced = moles of Ti produced * molar mass of Ti = 782.08 mol * 47.867 g/mol = 37,402.42 g = 37.4 kg

Therefore, when a reactor is charged with 61.0 kg of TiCl4 and 9.0 kg of Na, the amount of titanium produced is 37.4 kg.