For the emission spectrum of Be3+, calculate the lowest wavenumber νˉ (in inverse meters) of light produced by electron transitions between n=2, n=3, and n=4.
chemistry - DrBob222, Saturday, November 17, 2012 at 6:40pm
w = wavelength
1/w = RZ^2(1/n1^2 - 1/n2^2)
R = 1.09737E7
Z = 4
n1^2= 3^2= 9
n2^2 = 4^2 = 16
chemistry - amar chauhan, Saturday, November 17, 2012 at 11:28pm
chemistry - Chavan, Sunday, November 18, 2012 at 2:50am
What are the concepts used in these?