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Posted by on Saturday, November 17, 2012 at 5:44am.

For the emission spectrum of Be3+, calculate the lowest wavenumber νˉ (in inverse meters) of light produced by electron transitions between n=2, n=3, and n=4.

  • chemistry - , Saturday, November 17, 2012 at 6:40pm

    w = wavelength
    1/w = RZ^2(1/n1^2 - 1/n2^2)
    R = 1.09737E7
    Z = 4
    n1^2= 3^2= 9
    n2^2 = 4^2 = 16

  • chemistry - , Saturday, November 17, 2012 at 11:28pm

    8.56*10^6
    amar chauhan

  • chemistry - , Sunday, November 18, 2012 at 2:50am

    What are the concepts used in these?

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