Calculate the molarity of 38.5 mL of 1.80 M HNO3 diluted to 0.130 L with water
To calculate the molarity of the resulting solution, we can use the equation:
M1V1 = M2V2
Where:
M1 = initial molarity of the solution before dilution
V1 = initial volume of the solution before dilution
M2 = final molarity of the solution after dilution
V2 = final volume of the solution after dilution
Given:
M1 = 1.80 M
V1 = 38.5 mL = 0.0385 L
V2 = 0.130 L
Now let's substitute these values into the equation and solve for M2:
M1V1 = M2V2
(1.80 M)(0.0385 L) = M2(0.130 L)
M2 = (1.80 M)(0.0385 L) / (0.130 L)
M2 = 0.055 M
Therefore, the molarity of the resulting solution is 0.055 M.
To calculate the molarity of a solution, you need to use the equation:
M₁V₁ = M₂V₂
where M₁ is the initial molarity, V₁ is the initial volume, M₂ is the final molarity, and V₂ is the final volume.
In this case, the initial molarity (M₁) is 1.80 M, the initial volume (V₁) is 38.5 mL (which needs to be converted to liters), the final molarity (M₂) is what we want to find, and the final volume (V₂) is 0.130 L.
First, we need to convert the initial volume from milliliters to liters:
V₁ = 38.5 mL * (1 L / 1000 mL) = 0.0385 L
Substituting the values into the equation, we have:
(1.80 M) * (0.0385 L) = M₂ * (0.130 L)
Now we can solve for M₂:
M₂ = (1.80 M * 0.0385 L) / 0.130 L
M₂ = 0.53 M
Therefore, the molarity of the solution is 0.53 M.
Use the dilution formula of
c1v1 = c2v2
c = concn
v = volume