Thursday

January 29, 2015

January 29, 2015

Posted by **David** on Saturday, November 17, 2012 at 3:05am.

- math -
**Steve**, Saturday, November 17, 2012 at 6:23amacid in 400L 38% = 152

acid in 400L 65% = 260

if the 3 solutions were wanted in the amounts a,b,c respectively, then

a+b+c = 400

.3a + .4c + .8b = 260

.3a + .4b + .8c = 152

a = 340/3

b = 835/3

c = 25/3

check my results to make sure they fit the conditions.

**Answer this Question**

**Related Questions**

Math - a chemist has an 18% acid solution and a 36% acid solution. How many ...

algebra - Two acid solutions are available to a chemist. One is 10% nitric acid ...

Math - A chemist needs to mix an 18% acid solution with a 45% acid solution to ...

Algebra - A chemist has one solution that is 80% acid and a second solution that...

algebra - An industrial chemist will mix two acid solutions. One is 37% solution...

algebra - a chemist needs 10 liters of a 25% acid solution. the solution is to ...

algebra 2 - A chemist mixes some 20% acid solution with pure 100% acid to ...

algebra - A chemist mixes some 20% acid solution with pure 100% acid to increase...

Algebra 1 - A chemist has 10% acid solution and 60% acid solution. HOW many ...

Math - A chemistry teacher needs 2.5 liters of a sulfuric acid solution that is ...