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December 22, 2014

December 22, 2014

Posted by **Anonymous** on Saturday, November 17, 2012 at 1:13am.

- Calculus -
**Steve**, Saturday, November 17, 2012 at 6:10amlny = log_5(x) lnx

= lnx/ln5 lnx

= 1/ln5 ln^2(x)

1/y y' = 1/ln5 * 2lnx * 1/x

y' = 2y lnx / x ln5

= 2lnx/ln5 x^(log_5(x)-1)

= 2log_5(x) x^(log_5(x)-1)

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