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Posted by Anonymous on Saturday, November 17, 2012 at 1:13am.

y=x^logbase5(x)

lny = log_5(x) lnx = lnx/ln5 lnx = 1/ln5 ln^2(x) 1/y y' = 1/ln5 * 2lnx * 1/x y' = 2y lnx / x ln5 = 2lnx/ln5 x^(log_5(x)-1) = 2log_5(x) x^(log_5(x)-1)

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