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How many grams of solute are in 2.l L of 3.7Moles of Al(NO3)3

  • chemistry - ,

    I assume, although you don't strate it that way, that is 3.7M (as in molar and not mols).
    Then mols Al(NO3)3 =- M x L = ?
    and grams = mols x molar mass.

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