Tuesday

July 29, 2014

July 29, 2014

Posted by **Anonymous** on Saturday, November 17, 2012 at 12:10am.

- Calculus -
**Steve**, Saturday, November 17, 2012 at 12:43amf' = 6/√(1-x^8) * 4x^3 = 24x^3/√(1+x^8)

recall that f=6arcsin(x^4), so

sin(f/6) = x^4

1/6 cos(f/6) f' = 4x^3

f' = 24x^3/cos(f/6)

but cos(f/6) = √(1-sin^2(f/6)) = √(1-x^8)

**Related Questions**

Calculus - If f(x)=6arcsin(x^3) find f'(x)

Pre-Calculus/Calculus - I am too embarassed to ask this Calculus (really pre-...

Math:Calculus - Use the Fundamental Theorem of Calculus to find the derivative ...

Calculus Help - Use calculus to find the area A of the triangle with the given ...

math, calculus 2 - Use part 1 of the Fundamental Theorem of Calculus to find ...

Calculus - The area is bounded by y= x^3, x= 2 is rotated around the x-axis. ...

COLLEGE CALCULUS. HELP! - the fundamental theorem of calculus, f(x)=∫(0,x...

calculus - Find the arc length of the graph of y = x from x = 0 to x = 3 using ...

calculus help - Produce graphs of f that reveal all the important aspects of the...

Calculus AP need help! - Use Part 1 of the Fundamental Theorem of Calculus to ...