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Calculate the pH of a solution at 25.0 °C that contains 1.94 × 10-10 M hydronium ions.

  • Chemistry -

    I would convert 1.94E-10 to pOH.
    pOH = -log(OH^-), then
    pH + pOH = pKw = 14.
    You know pOH and pKw, solve for pH.

    If you prefer you can do it this way(H^+)(OH^-) = Kw = 1E-14
    You have OH^-, solve for (H^+), then
    pH = -log(H^+)

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