Sunday

December 21, 2014

December 21, 2014

Posted by **Anonymous** on Friday, November 16, 2012 at 11:46pm.

dy/dx=?

- Calculus -
**Steve**, Saturday, November 17, 2012 at 5:51amsince (√(9x^2-1))^2 = 9x^2-1,

I assume you mean arctan^2 √(9x^2-1)

let u = 9x^2-1

y = arctan^2 (√u)

y' = 2 arctan(√u) * 1/(u+1) * 1/(2√u) u'

= 2 arctan(√9x^2-1) * 1/(9x^2) * 1/(2√(9x^2-1)) * 18x

= 2 arctan(√9x^2-1) / [x √(9x^2-1)]

**Answer this Question**

**Related Questions**

Calculus - 1.Evaluate: (1/(x*sqrt(x^2-4)) I know the answer is -1/2*arctan(2/...

calculus - Let f be a function defined by f(x)= arctan x/2 + arctan x. the value...

calculus - Integrate sqrt(x^2 + 1) dx over [0,2*pi] I can substitute u=arctan x ...

precal - The values of x that are solutions to the equation cos^(2)x=sin2x in ...

calculus - find the derivative of y=sqrt of arctan x

Calc - Evaluate the integral (3x+4)/[(x^2+4)(3-x)]dx a. (1/2)ln(x^2+4) + ln|3-x...

PreCalculus - I'm unsure how to even start this problem Solve for x: Arctan( -4/...

Trigonometry - I need help with I just can't seem to get anywhere. this is as ...

calculus - h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du...

calculus - h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du...