Posted by **jason** on Friday, November 16, 2012 at 10:48pm.

An outfielder throws a 1.88 kg baseball at a

speed of 57 m/s and an initial angle of 10.2.

What is the kinetic energy of the ball at the

highest point of its motion?

Answer in units of J

- Physics -
**Sabrina**, Saturday, October 31, 2015 at 7:50pm
To find the KE of the ball at the highest ball of motion, we have to use the initial velocity and angle to find the horizontal velocity.

V(horizontal) = V(initial) * cos(theta)

V(horizontal) = (57 m/s) * cos(10.2)

V(horizontal) = 56.099 m/s

Using the velocity in the horizontal direction that we found, along with the mass given, we can calculate the KE of the ball at its highest point.

KE = (1/2)mv^2

KE = (1/2)(1.88 kg)(56.099 m/s)^2

KE = 2958.27 J

## Answer This Question

## Related Questions

- physics - An outfielder throws a 0.150-kg baseball at a speed of 50.0 m/s and an...
- Physics - An outfielder throws a 0.150 kg baseball at a speed of 26.0 m/s and an...
- science - An outfielder throws a .150 kg baseball at a speed of 40.0 m/s and an ...
- Physics - An outﬁelder throws a 1.05 kg baseball at a speed of 99 m/s and...
- Physics - An outfielder throws a 0.145 kg baseball to the shortstop with a ...
- physics - An outfielder throws a baseball with an initial speed of 30 m/s at an ...
- Physics - An outfielder throws a baseball to home plate with a velocity of +15 ...
- PHYSICS - A 48.7-g golf ball is driven from the tee with an initial speed of 47....
- PHYSICS - A 50.5-g golf ball is driven from the tee with an initial speed of 57....
- physic - A 47.5-g golf ball is driven from the tee with an initial speed of 41.8...

More Related Questions