Posted by **BA** on Friday, November 16, 2012 at 10:43pm.

A recording camera is located 2500 feet from the launch pad for recording a rocket launch. As the rocket lifts off, the angle of elevation of the camera increases 4 degrees per second while recording the launch. Find the instantaneous velocity and acceleration of the rocket at time t>0.

- Calculus -
**Steve**, Saturday, November 17, 2012 at 12:40am
using ' to denote d/dt, the height h is

h = 2500 tanθ

h' = 2500 sec^2 θ θ'

at t=0, θ'=4*pi/180

h' = 2500 * 4pi/180 = 5.55 ft/s

h'' = 2500 sec^2θ (2tanθ θ' + θ'')

- Calculus -
**BA**, Saturday, November 17, 2012 at 12:54am
Thanks, but how do you find the instantaneous velocity from that? I know that acceleration is the derivative from the equation of Instantaneous velocity.. but I don't know how to get the equation for it.

- Calculus -
**BA**, Saturday, November 17, 2012 at 1:00am
Nevermind, I see what you did. Thank you!

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